\begin{eqnarray*}
B_1&=&2\biggl(1+\frac{2}{x}\left(\zm+3\right)+\frac{4}{x^2}\biggr)\\
B_2&=&-\zm-2-\frac{2}{x}z^2-\frac{4}{x^2} z^2\\
B_3&=&2z^2\biggl(1+\frac{2}{x}\biggr)\\
B_4&=&-\zm-2-\frac{2}{x}\left(\zm-1\right)-\frac{8}{x^2}\zm
      -\frac{8}{x^3}z^2\\
B_5&=&2\biggl(1+\frac{2}{x}\left(\zm+2\right)+\frac{2}{x^2}\left(\zm+2\right)
      \biggr)\\
B_6&=&2z^2\biggl(1+\frac{3}{x}+\frac{2}{x^2}\biggr)\\
B_7&=&-\zm-2-\frac{4}{x}z^2-\frac{4}{x^2}
      z^2\\
B_8&=&-\zm-2-\frac{4}{x}\zm-\frac{8}{x^2}\zm-\frac{8}{x^3}z^2\\
B_9&=&2z^2\biggl(1+\frac{4}{x}+\frac{4}{x^2}\biggr)\\
B_{10}&=&2\biggl(1+\frac{2}{x}z^2+\frac{4}{x^2}
       z^2\biggr)\\
\end{eqnarray*}

